Base | Representation |
---|---|
bin | 11001110001001100110000… |
… | …111100100100000001110010 |
3 | 112212021110000112020211220002 |
4 | 121301030300330210001302 |
5 | 104323313142021102010 |
6 | 1041012020400350002 |
7 | 32604655443551201 |
oct | 3161146074440162 |
9 | 485243015224802 |
10 | 113332123222130 |
11 | 33124979aa642a |
12 | 10864636915302 |
13 | 4b31233b53ab7 |
14 | 1ddb438397238 |
15 | d180668421a5 |
hex | 671330f24072 |
113332123222130 has 64 divisors (see below), whose sum is σ = 204613156892160. Its totient is φ = 45196334919936.
The previous prime is 113332123222069. The next prime is 113332123222207. The reversal of 113332123222130 is 31222321233311.
113332123222130 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 113332123222093 and 113332123222102.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 34839261584 + ... + 34839264836.
It is an arithmetic number, because the mean of its divisors is an integer number (3197080576440).
Almost surely, 2113332123222130 is an apocalyptic number.
113332123222130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
113332123222130 is a deficient number, since it is larger than the sum of its proper divisors (91281033670030).
113332123222130 is a wasteful number, since it uses less digits than its factorization.
113332123222130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9075.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 113332123222130 its reverse (31222321233311), we get a palindrome (144554444455441).
The spelling of 113332123222130 in words is "one hundred thirteen trillion, three hundred thirty-two billion, one hundred twenty-three million, two hundred twenty-two thousand, one hundred thirty".
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