Base | Representation |
---|---|
bin | 11001110001001100111100… |
… | …000101110111101010011111 |
3 | 112212021110111120002212201100 |
4 | 121301030330011313222133 |
5 | 104323314032403224411 |
6 | 1041012051120244143 |
7 | 32604663204126006 |
oct | 3161147405675237 |
9 | 485243446085640 |
10 | 113332310211231 |
11 | 33124a65602081 |
12 | 10864689470653 |
13 | 4b31263803c37 |
14 | 1ddb45514dc3d |
15 | d18077e7b456 |
hex | 67133c177a9f |
113332310211231 has 48 divisors (see below), whose sum is σ = 170598888720000. Its totient is φ = 72410975669760.
The previous prime is 113332310211229. The next prime is 113332310211233. The reversal of 113332310211231 is 132112013233311.
113332310211231 is a `hidden beast` number, since 1 + 1 + 3 + 3 + 323 + 102 + 1 + 1 + 231 = 666.
It is an interprime number because it is at equal distance from previous prime (113332310211229) and next prime (113332310211233).
It is not a de Polignac number, because 113332310211231 - 21 = 113332310211229 is a prime.
It is a super-2 number, since 2×1133323102112312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113332310211195 and 113332310211204.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113332310211233) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 56610730 + ... + 58578488.
It is an arithmetic number, because the mean of its divisors is an integer number (3554143515000).
Almost surely, 2113332310211231 is an apocalyptic number.
113332310211231 is a deficient number, since it is larger than the sum of its proper divisors (57266578508769).
113332310211231 is a wasteful number, since it uses less digits than its factorization.
113332310211231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1969424 (or 1969421 counting only the distinct ones).
The product of its (nonzero) digits is 1944, while the sum is 27.
Adding to 113332310211231 its reverse (132112013233311), we get a palindrome (245444323444542).
The spelling of 113332310211231 in words is "one hundred thirteen trillion, three hundred thirty-two billion, three hundred ten million, two hundred eleven thousand, two hundred thirty-one".
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