Base | Representation |
---|---|
bin | 11001110001001101100101… |
… | …010101101001001100011111 |
3 | 112212021112021210020011111011 |
4 | 121301031211111221030133 |
5 | 104323321442031242002 |
6 | 1041012243520240051 |
7 | 32605016306053225 |
oct | 3161154525511437 |
9 | 485245253204434 |
10 | 113333002212127 |
11 | 33125290188645 |
12 | 10864841170027 |
13 | 4b31343ca2419 |
14 | 1ddb4bd004b15 |
15 | d180b8abd8d7 |
hex | 67136556931f |
113333002212127 has 2 divisors, whose sum is σ = 113333002212128. Its totient is φ = 113333002212126.
The previous prime is 113333002212113. The next prime is 113333002212173. The reversal of 113333002212127 is 721212200333311.
It is a weak prime.
It is an emirp because it is prime and its reverse (721212200333311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113333002212127 - 211 = 113333002210079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113333002219127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56666501106063 + 56666501106064.
It is an arithmetic number, because the mean of its divisors is an integer number (56666501106064).
Almost surely, 2113333002212127 is an apocalyptic number.
113333002212127 is a deficient number, since it is larger than the sum of its proper divisors (1).
113333002212127 is an equidigital number, since it uses as much as digits as its factorization.
113333002212127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9072, while the sum is 31.
Adding to 113333002212127 its reverse (721212200333311), we get a palindrome (834545202545438).
The spelling of 113333002212127 in words is "one hundred thirteen trillion, three hundred thirty-three billion, two million, two hundred twelve thousand, one hundred twenty-seven".
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