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1133440031413 is a prime number
BaseRepresentation
bin10000011111100110010…
…010100101101010110101
311000100121101101101001201
4100133212102211222311
5122032241122001123
62224410053252501
7144613462206334
oct20374622455265
94010541341051
101133440031413
113a7764392598
12163802934131
1382b62a71101
143cc0473dd1b
151e73b5dd5ad
hex107e64a5ab5

1133440031413 has 2 divisors, whose sum is σ = 1133440031414. Its totient is φ = 1133440031412.

The previous prime is 1133440031407. The next prime is 1133440031417. The reversal of 1133440031413 is 3141300443311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1090650212964 + 42789818449 = 1044342^2 + 206857^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1133440031413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1133440031417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566720015706 + 566720015707.

It is an arithmetic number, because the mean of its divisors is an integer number (566720015707).

Almost surely, 21133440031413 is an apocalyptic number.

It is an amenable number.

1133440031413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1133440031413 is an equidigital number, since it uses as much as digits as its factorization.

1133440031413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1133440031413 its reverse (3141300443311), we get a palindrome (4274740474724).

The spelling of 1133440031413 in words is "one trillion, one hundred thirty-three billion, four hundred forty million, thirty-one thousand, four hundred thirteen".