Base | Representation |
---|---|
bin | 11001110001011000000011… |
… | …010000010101011100011111 |
3 | 112212022121022002000221201222 |
4 | 121301120003100111130133 |
5 | 104324013001314231411 |
6 | 1041021343054323555 |
7 | 32605564652644331 |
oct | 3161300320253437 |
9 | 485277262027658 |
10 | 113344241555231 |
11 | 3312a028530455 |
12 | 10866a591b95bb |
13 | 4b3241567a8bb |
14 | 1ddbc679b9451 |
15 | d185256894db |
hex | 67160341571f |
113344241555231 has 2 divisors, whose sum is σ = 113344241555232. Its totient is φ = 113344241555230.
The previous prime is 113344241555137. The next prime is 113344241555341. The reversal of 113344241555231 is 132555142443311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113344241555231 - 210 = 113344241554207 is a prime.
It is a super-2 number, since 2×1133442415552312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113344241555731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56672120777615 + 56672120777616.
It is an arithmetic number, because the mean of its divisors is an integer number (56672120777616).
Almost surely, 2113344241555231 is an apocalyptic number.
113344241555231 is a deficient number, since it is larger than the sum of its proper divisors (1).
113344241555231 is an equidigital number, since it uses as much as digits as its factorization.
113344241555231 is an evil number, because the sum of its binary digits is even.
The product of its digits is 864000, while the sum is 44.
Adding to 113344241555231 its reverse (132555142443311), we get a palindrome (245899383998542).
The spelling of 113344241555231 in words is "one hundred thirteen trillion, three hundred forty-four billion, two hundred forty-one million, five hundred fifty-five thousand, two hundred thirty-one".
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