113345437 has 2 divisors, whose sum is σ = 113345438. Its totient is φ = 113345436.

The previous prime is 113345417. The next prime is 113345447. The reversal of 113345437 is 734543311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70913241 + 42432196 = 8421^2 + 6514^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113345437 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 113345399 and 113345408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113345417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56672718 + 56672719.

It is an arithmetic number, because the mean of its divisors is an integer number (56672719).

Almost surely, 2^113345437 is an apocalyptic number.

It is an amenable number.

113345437 is a deficient number, since it is larger than the sum of its proper divisors (1).

113345437 is an equidigital number, since it uses as much as digits as its factorization.

113345437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 15120, while the sum is 31.

The square root of 113345437 is about 10646.3814040264. The cubic root of 113345437 is about 483.9509503944.

Adding to 113345437 its reverse (734543311), we get a palindrome (847888748).

The spelling of 113345437 in words is "one hundred thirteen million, three hundred forty-five thousand, four hundred thirty-seven".