Base | Representation |
---|---|
bin | 11001110001011111001000… |
… | …111000000011011011011111 |
3 | 112212100022221110111221111012 |
4 | 121301133020320003123133 |
5 | 104324124043110433142 |
6 | 1041025042201445435 |
7 | 32606254364025236 |
oct | 3161371070033337 |
9 | 485308843457435 |
10 | 113351852046047 |
11 | 3313228344888a |
12 | 10868421aa087b |
13 | 4b330592b34c4 |
14 | 1ddc38a64db1d |
15 | d1881d894882 |
hex | 6717c8e036df |
113351852046047 has 2 divisors, whose sum is σ = 113351852046048. Its totient is φ = 113351852046046.
The previous prime is 113351852046031. The next prime is 113351852046071. The reversal of 113351852046047 is 740640258153311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113351852046047 - 24 = 113351852046031 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113351852045986 and 113351852046004.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113351852046847) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56675926023023 + 56675926023024.
It is an arithmetic number, because the mean of its divisors is an integer number (56675926023024).
Almost surely, 2113351852046047 is an apocalyptic number.
113351852046047 is a deficient number, since it is larger than the sum of its proper divisors (1).
113351852046047 is an equidigital number, since it uses as much as digits as its factorization.
113351852046047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2419200, while the sum is 50.
The spelling of 113351852046047 in words is "one hundred thirteen trillion, three hundred fifty-one billion, eight hundred fifty-two million, forty-six thousand, forty-seven".
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