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11335325433342 = 239719476504181
BaseRepresentation
bin1010010011110011011000…
…0010111011110111111110
31111010122110022121122121120
42210330312002323313332
52441204221302331332
640035213203211410
72246643634300401
oct244746602736776
944118408548546
1011335325433342
113680314772119
121330a41676b66
13642bbba0a931
142b28c00d7d38
15149cd027d32c
hexa4f360bbdfe

11335325433342 has 16 divisors (see below), whose sum is σ = 22904368918032. Its totient is φ = 3739488802560.

The previous prime is 11335325433331. The next prime is 11335325433389. The reversal of 11335325433342 is 24333452353311.

It is a junction number, because it is equal to n+sod(n) for n = 11335325433294 and 11335325433303.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9738251509 + ... + 9738252672.

It is an arithmetic number, because the mean of its divisors is an integer number (1431523057377).

Almost surely, 211335325433342 is an apocalyptic number.

11335325433342 is an abundant number, since it is smaller than the sum of its proper divisors (11569043484690).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11335325433342 is a wasteful number, since it uses less digits than its factorization.

11335325433342 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19476504283.

The product of its digits is 1166400, while the sum is 42.

Adding to 11335325433342 its reverse (24333452353311), we get a palindrome (35668777786653).

The spelling of 11335325433342 in words is "eleven trillion, three hundred thirty-five billion, three hundred twenty-five million, four hundred thirty-three thousand, three hundred forty-two".

Divisors: 1 2 3 6 97 194 291 582 19476504181 38953008362 58429512543 116859025086 1889220905557 3778441811114 5667662716671 11335325433342