Search a number
-
+
11336144890541 is a prime number
BaseRepresentation
bin1010010011110110011011…
…1000111010101010101101
31111010201120102120101120012
42210331212320322222231
52441212411042444131
640035430355103005
72250003144462422
oct244754670725255
944121512511505
1011336144890541
1136806a5292479
12133102bba1a65
13642cbc713b53
142b295ac89d49
15149d2c19a52b
hexa4f66e3aaad

11336144890541 has 2 divisors, whose sum is σ = 11336144890542. Its totient is φ = 11336144890540.

The previous prime is 11336144890531. The next prime is 11336144890571. The reversal of 11336144890541 is 14509844163311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11084571422500 + 251573468041 = 3329350^2 + 501571^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11336144890541 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11336144890541.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11336144890531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5668072445270 + 5668072445271.

It is an arithmetic number, because the mean of its divisors is an integer number (5668072445271).

Almost surely, 211336144890541 is an apocalyptic number.

It is an amenable number.

11336144890541 is a deficient number, since it is larger than the sum of its proper divisors (1).

11336144890541 is an equidigital number, since it uses as much as digits as its factorization.

11336144890541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1244160, while the sum is 50.

The spelling of 11336144890541 in words is "eleven trillion, three hundred thirty-six billion, one hundred forty-four million, eight hundred ninety thousand, five hundred forty-one".