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1133646528097 is a prime number
BaseRepresentation
bin10000011111110010100…
…110010011111001100001
311000101010202221111021001
4100133302212103321201
5122033202002344342
62224442351232001
7144621550332436
oct20376246237141
94011122844231
101133646528097
113a785aa02606
1216385bb18601
1382b967914b5
143cc23d33b8d
151e74e7cc8b7
hex107f2993e61

1133646528097 has 2 divisors, whose sum is σ = 1133646528098. Its totient is φ = 1133646528096.

The previous prime is 1133646528089. The next prime is 1133646528143. The reversal of 1133646528097 is 7908256463311.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 863122753936 + 270523774161 = 929044^2 + 520119^2 .

It is an emirp because it is prime and its reverse (7908256463311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1133646528097 - 23 = 1133646528089 is a prime.

It is not a weakly prime, because it can be changed into another prime (1133646522097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566823264048 + 566823264049.

It is an arithmetic number, because the mean of its divisors is an integer number (566823264049).

It is a 1-persistent number, because it is pandigital, but 2⋅1133646528097 = 2267293056194 is not.

Almost surely, 21133646528097 is an apocalyptic number.

It is an amenable number.

1133646528097 is a deficient number, since it is larger than the sum of its proper divisors (1).

1133646528097 is an equidigital number, since it uses as much as digits as its factorization.

1133646528097 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6531840, while the sum is 55.

The spelling of 1133646528097 in words is "one trillion, one hundred thirty-three billion, six hundred forty-six million, five hundred twenty-eight thousand, ninety-seven".