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11338473401819 is a prime number
BaseRepresentation
bin1010010011111111000110…
…1011011110110111011011
31111010221120201002000112122
42210333301223132313123
52441232143142324234
640040453415131455
72250114640502144
oct244776153366733
944127521060478
1011338473401819
11368168a707463
12133157b973b8b
136432a0c5c485
142b2adc21aacb
15149e167ee92e
hexa4ff1adeddb

11338473401819 has 2 divisors, whose sum is σ = 11338473401820. Its totient is φ = 11338473401818.

The previous prime is 11338473401797. The next prime is 11338473401831. The reversal of 11338473401819 is 91810437483311.

It is a strong prime.

It is an emirp because it is prime and its reverse (91810437483311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11338473401819 - 212 = 11338473397723 is a prime.

It is a super-2 number, since 2×113384734018192 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11338473451819) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5669236700909 + 5669236700910.

It is an arithmetic number, because the mean of its divisors is an integer number (5669236700910).

Almost surely, 211338473401819 is an apocalyptic number.

11338473401819 is a deficient number, since it is larger than the sum of its proper divisors (1).

11338473401819 is an equidigital number, since it uses as much as digits as its factorization.

11338473401819 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1741824, while the sum is 53.

The spelling of 11338473401819 in words is "eleven trillion, three hundred thirty-eight billion, four hundred seventy-three million, four hundred one thousand, eight hundred nineteen".