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113384887001 is a prime number
BaseRepresentation
bin110100110011001000…
…1000001001011011001
3101211122222200001102022
41221212101001023121
53324203012341001
6124031023344225
711122532431451
oct1514621011331
9354588601368
10113384887001
11440a48a3891
1219b84452075
13a8cc860b19
1456b8978d61
152e3936711b
hex1a664412d9

113384887001 has 2 divisors, whose sum is σ = 113384887002. Its totient is φ = 113384887000.

The previous prime is 113384886959. The next prime is 113384887003. The reversal of 113384887001 is 100788483311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 94153854025 + 19231032976 = 306845^2 + 138676^2 .

It is an emirp because it is prime and its reverse (100788483311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113384887001 is a prime.

It is a super-2 number, since 2×1133848870012 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 113384887003, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (113384887003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56692443500 + 56692443501.

It is an arithmetic number, because the mean of its divisors is an integer number (56692443501).

Almost surely, 2113384887001 is an apocalyptic number.

It is an amenable number.

113384887001 is a deficient number, since it is larger than the sum of its proper divisors (1).

113384887001 is an equidigital number, since it uses as much as digits as its factorization.

113384887001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 129024, while the sum is 44.

The spelling of 113384887001 in words is "one hundred thirteen billion, three hundred eighty-four million, eight hundred eighty-seven thousand, one".