Base | Representation |
---|---|
bin | 1010010100000011000100… |
… | …0001010010001100100111 |
3 | 1111011001022202200202021212 |
4 | 2211000301001102030213 |
5 | 2441241332214103303 |
6 | 40041151100102035 |
7 | 2250153163231214 |
oct | 245006101221447 |
9 | 44131282622255 |
10 | 11339536081703 |
11 | 36820855515a5 |
12 | 133181783491b |
13 | 64341017433b |
14 | 2b2b9d402b0b |
15 | 149e79c62ad8 |
hex | a5031052327 |
11339536081703 has 2 divisors, whose sum is σ = 11339536081704. Its totient is φ = 11339536081702.
The previous prime is 11339536081649. The next prime is 11339536081711. The reversal of 11339536081703 is 30718063593311.
It is a strong prime.
It is an emirp because it is prime and its reverse (30718063593311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11339536081703 - 212 = 11339536077607 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11339536011703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5669768040851 + 5669768040852.
It is an arithmetic number, because the mean of its divisors is an integer number (5669768040852).
Almost surely, 211339536081703 is an apocalyptic number.
11339536081703 is a deficient number, since it is larger than the sum of its proper divisors (1).
11339536081703 is an equidigital number, since it uses as much as digits as its factorization.
11339536081703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1224720, while the sum is 50.
The spelling of 11339536081703 in words is "eleven trillion, three hundred thirty-nine billion, five hundred thirty-six million, eighty-one thousand, seven hundred three".
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