Base | Representation |
---|---|
bin | 11001110010001100001010… |
… | …110001101000101110001100 |
3 | 112212111221202002001100101201 |
4 | 121302030022301220232030 |
5 | 104330422103242102200 |
6 | 1041103200031315244 |
7 | 32612615504302516 |
oct | 3162141261505614 |
9 | 485457662040351 |
10 | 113400202300300 |
11 | 331508349524a3 |
12 | 1087587637bb24 |
13 | 4b377933209c6 |
14 | 2000855c1abb6 |
15 | d19bed4b0c6a |
hex | 67230ac68b8c |
113400202300300 has 18 divisors (see below), whose sum is σ = 246078438991868. Its totient is φ = 45360080920080.
The previous prime is 113400202300289. The next prime is 113400202300379. The reversal of 113400202300300 is 3003202004311.
It is a super-2 number, since 2×1134002023003002 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 567001011402 + ... + 567001011601.
Almost surely, 2113400202300300 is an apocalyptic number.
113400202300300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113400202300300 is an abundant number, since it is smaller than the sum of its proper divisors (132678236691568).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113400202300300 is a wasteful number, since it uses less digits than its factorization.
113400202300300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1134002023017 (or 1134002023010 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 113400202300300 its reverse (3003202004311), we get a palindrome (116403404304611).
The spelling of 113400202300300 in words is "one hundred thirteen trillion, four hundred billion, two hundred two million, three hundred thousand, three hundred".
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