Base | Representation |
---|---|
bin | 10101000111110101… |
… | …10000110101001010 |
3 | 1002021022020222001221 |
4 | 22203322300311022 |
5 | 141211021301122 |
6 | 5113132032254 |
7 | 551005423564 |
oct | 124372606512 |
9 | 32238228057 |
10 | 11340025162 |
11 | 489a16a824 |
12 | 224590268a |
13 | 10b94ca57b |
14 | 798102334 |
15 | 4658576c7 |
hex | 2a3eb0d4a |
11340025162 has 4 divisors (see below), whose sum is σ = 17010037746. Its totient is φ = 5670012580.
The previous prime is 11340025129. The next prime is 11340025223. The reversal of 11340025162 is 26152004311.
It is a happy number.
11340025162 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 26152004311 = 281 ⋅93067631.
It can be written as a sum of positive squares in only one way, i.e., 6206445961 + 5133579201 = 78781^2 + 71649^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2835006289 + ... + 2835006292.
Almost surely, 211340025162 is an apocalyptic number.
11340025162 is a deficient number, since it is larger than the sum of its proper divisors (5670012584).
11340025162 is an equidigital number, since it uses as much as digits as its factorization.
11340025162 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5670012583.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 11340025162 its reverse (26152004311), we get a palindrome (37492029473).
The spelling of 11340025162 in words is "eleven billion, three hundred forty million, twenty-five thousand, one hundred sixty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •