Base | Representation |
---|---|
bin | 10000100000000111111… |
… | …010010110010001100011 |
3 | 11000102001200210010202221 |
4 | 100200013322112101203 |
5 | 122034420022232433 |
6 | 2224542043251511 |
7 | 144633451553605 |
oct | 20400772262143 |
9 | 4012050703687 |
10 | 1134004102243 |
11 | 3a7a23830331 |
12 | 16393b819b97 |
13 | 82c2289a02c |
14 | 3cc59613175 |
15 | 1e770db072d |
hex | 10807e96463 |
1134004102243 has 2 divisors, whose sum is σ = 1134004102244. Its totient is φ = 1134004102242.
The previous prime is 1134004102183. The next prime is 1134004102249. The reversal of 1134004102243 is 3422014004311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1134004102243 is a prime.
It is not a weakly prime, because it can be changed into another prime (1134004102249) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567002051121 + 567002051122.
It is an arithmetic number, because the mean of its divisors is an integer number (567002051122).
Almost surely, 21134004102243 is an apocalyptic number.
1134004102243 is a deficient number, since it is larger than the sum of its proper divisors (1).
1134004102243 is an equidigital number, since it uses as much as digits as its factorization.
1134004102243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 1134004102243 its reverse (3422014004311), we get a palindrome (4556018106554).
The spelling of 1134004102243 in words is "one trillion, one hundred thirty-four billion, four million, one hundred two thousand, two hundred forty-three".
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