Base | Representation |
---|---|
bin | 110100110011100110… |
… | …0101101000001111001 |
3 | 101211201002002221211221 |
4 | 1221213030231001321 |
5 | 3324221014024423 |
6 | 124032342552041 |
7 | 11123112425110 |
oct | 1514714550171 |
9 | 354632087757 |
10 | 113400533113 |
11 | 4410270aa5a |
12 | 19b89738621 |
13 | a902b7b58a |
14 | 56baa8cc77 |
15 | 2e3a907e5d |
hex | 1a6732d079 |
113400533113 has 16 divisors (see below), whose sum is σ = 131775565824. Its totient is φ = 95570458560.
The previous prime is 113400533093. The next prime is 113400533161. The reversal of 113400533113 is 311335004311.
It is a cyclic number.
It is not a de Polignac number, because 113400533113 - 233 = 104810598521 is a prime.
It is not an unprimeable number, because it can be changed into a prime (113400533513) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1097931 + ... + 1196767.
It is an arithmetic number, because the mean of its divisors is an integer number (8235972864).
Almost surely, 2113400533113 is an apocalyptic number.
It is an amenable number.
113400533113 is a deficient number, since it is larger than the sum of its proper divisors (18375032711).
113400533113 is an equidigital number, since it uses as much as digits as its factorization.
113400533113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 101592.
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 113400533113 its reverse (311335004311), we get a palindrome (424735537424).
The spelling of 113400533113 in words is "one hundred thirteen billion, four hundred million, five hundred thirty-three thousand, one hundred thirteen".
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