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113401331214103 is a prime number
BaseRepresentation
bin11001110010001101001110…
…000100000110011100010111
3112212112001122202022010000001
4121302031032010012130113
5104330431411242322403
61041103504040032131
732612655463021432
oct3162151604063427
9485461582263001
10113401331214103
1133151264116109
1210875b30462647
134b3791318613a
142000921b24819
15d19c67658c1d
hex67234e106717

113401331214103 has 2 divisors, whose sum is σ = 113401331214104. Its totient is φ = 113401331214102.

The previous prime is 113401331214079. The next prime is 113401331214113. The reversal of 113401331214103 is 301412133104311.

It is a strong prime.

It is an emirp because it is prime and its reverse (301412133104311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113401331214103 is a prime.

It is a super-2 number, since 2×1134013312141032 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113401331214113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56700665607051 + 56700665607052.

It is an arithmetic number, because the mean of its divisors is an integer number (56700665607052).

Almost surely, 2113401331214103 is an apocalyptic number.

113401331214103 is a deficient number, since it is larger than the sum of its proper divisors (1).

113401331214103 is an equidigital number, since it uses as much as digits as its factorization.

113401331214103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 28.

Adding to 113401331214103 its reverse (301412133104311), we get a palindrome (414813464318414).

The spelling of 113401331214103 in words is "one hundred thirteen trillion, four hundred one billion, three hundred thirty-one million, two hundred fourteen thousand, one hundred three".