Base | Representation |
---|---|
bin | 10101000111110110… |
… | …11101111101100111 |
3 | 1002021022121100122122 |
4 | 22203323131331213 |
5 | 141211043210043 |
6 | 5113140020155 |
7 | 551010123542 |
oct | 124373357547 |
9 | 32238540578 |
10 | 11340210023 |
11 | 489a2866aa |
12 | 224599165b |
13 | 10b956375c |
14 | 79814d859 |
15 | 465892368 |
hex | 2a3eddf67 |
11340210023 has 2 divisors, whose sum is σ = 11340210024. Its totient is φ = 11340210022.
The previous prime is 11340209989. The next prime is 11340210041. The reversal of 11340210023 is 32001204311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11340210023 - 232 = 7045242727 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11340209983 and 11340210010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11340215023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5670105011 + 5670105012.
It is an arithmetic number, because the mean of its divisors is an integer number (5670105012).
Almost surely, 211340210023 is an apocalyptic number.
11340210023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11340210023 is an equidigital number, since it uses as much as digits as its factorization.
11340210023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 11340210023 its reverse (32001204311), we get a palindrome (43341414334).
The spelling of 11340210023 in words is "eleven billion, three hundred forty million, two hundred ten thousand, twenty-three".
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