Base | Representation |
---|---|
bin | 110100110011101101… |
… | …0011011100001010101 |
3 | 101211201022212202210022 |
4 | 1221213122123201111 |
5 | 3324222424201123 |
6 | 124032552034525 |
7 | 11123155132556 |
oct | 1514732334125 |
9 | 354638782708 |
10 | 113404131413 |
11 | 44104748461 |
12 | 19b8a992a45 |
13 | a90383b351 |
14 | 56bb34832d |
15 | 2e3adb91c8 |
hex | 1a6769b855 |
113404131413 has 2 divisors, whose sum is σ = 113404131414. Its totient is φ = 113404131412.
The previous prime is 113404131409. The next prime is 113404131419. The reversal of 113404131413 is 314131404311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 79672401169 + 33731730244 = 282263^2 + 183662^2 .
It is an emirp because it is prime and its reverse (314131404311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113404131413 - 22 = 113404131409 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113404131419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56702065706 + 56702065707.
It is an arithmetic number, because the mean of its divisors is an integer number (56702065707).
Almost surely, 2113404131413 is an apocalyptic number.
It is an amenable number.
113404131413 is a deficient number, since it is larger than the sum of its proper divisors (1).
113404131413 is an equidigital number, since it uses as much as digits as its factorization.
113404131413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 113404131413 its reverse (314131404311), we get a palindrome (427535535724).
The spelling of 113404131413 in words is "one hundred thirteen billion, four hundred four million, one hundred thirty-one thousand, four hundred thirteen".
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