113410041240132 has 72 divisors (see below), whose sum is σ = 352831239423936. Its totient is φ = 29910340545984.

The previous prime is 113410041239947. The next prime is 113410041240149. The reversal of 113410041240132 is 231042140014311.

It is a happy number.

113410041240132 is a `hidden beast` number, since 1 + 1 + 3 + 410 + 0 + 4 + 1 + 240 + 1 + 3 + 2 = 666.

It is a super-3 number, since 3×113410041240132³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113410041240096 and 113410041240105.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 17309221578 + ... + 17309228129.

It is an arithmetic number, because the mean of its divisors is an integer number (4900433880888).

Almost surely, 2^{113410041240132} is an apocalyptic number.

113410041240132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

113410041240132 is an abundant number, since it is smaller than the sum of its proper divisors (239421198183804).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113410041240132 is a wasteful number, since it uses less digits than its factorization.

113410041240132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34618449737 (or 34618449732 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 27.

Adding to 113410041240132 its reverse (231042140014311), we get a palindrome (344452181254443).

The spelling of 113410041240132 in words is "one hundred thirteen trillion, four hundred ten billion, forty-one million, two hundred forty thousand, one hundred thirty-two".