Base | Representation |
---|---|
bin | 1010010100001000100101… |
… | …1111100000111001011001 |
3 | 1111011012011012200222220120 |
4 | 2211002021133200321121 |
5 | 2441302402210314431 |
6 | 40041554242143453 |
7 | 2250235025600346 |
oct | 245021137407131 |
9 | 44135135628816 |
10 | 11341020401241 |
11 | 36827773a1863 |
12 | 1331b70951b89 |
13 | 6435b883631b |
14 | 2b2ca05c37cd |
15 | 14a015211196 |
hex | a50897e0e59 |
11341020401241 has 32 divisors (see below), whose sum is σ = 15219069844608. Its totient is φ = 7511932538880.
The previous prime is 11341020401239. The next prime is 11341020401281. The reversal of 11341020401241 is 14210402014311.
It is a happy number.
It is not a de Polignac number, because 11341020401241 - 21 = 11341020401239 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11341020401201) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2165554075 + ... + 2165559311.
It is an arithmetic number, because the mean of its divisors is an integer number (475595932644).
Almost surely, 211341020401241 is an apocalyptic number.
It is an amenable number.
11341020401241 is a deficient number, since it is larger than the sum of its proper divisors (3878049443367).
11341020401241 is a wasteful number, since it uses less digits than its factorization.
11341020401241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9481.
The product of its (nonzero) digits is 768, while the sum is 24.
Adding to 11341020401241 its reverse (14210402014311), we get a palindrome (25551422415552).
The spelling of 11341020401241 in words is "eleven trillion, three hundred forty-one billion, twenty million, four hundred one thousand, two hundred forty-one".
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