Base | Representation |
---|---|
bin | 10000100000001110001… |
… | …111001000100010110011 |
3 | 11000102100002110012011222 |
4 | 100200032033020202303 |
5 | 122040124203324243 |
6 | 2225000353455255 |
7 | 144636210523352 |
oct | 20401617104263 |
9 | 4012302405158 |
10 | 1134110214323 |
11 | 3a7a78716969 |
12 | 16396b27152b |
13 | 82c3b870848 |
14 | 3cc69755999 |
15 | 1e77a371168 |
hex | 1080e3c88b3 |
1134110214323 has 2 divisors, whose sum is σ = 1134110214324. Its totient is φ = 1134110214322.
The previous prime is 1134110214317. The next prime is 1134110214329. The reversal of 1134110214323 is 3234120114311.
It is a balanced prime because it is at equal distance from previous prime (1134110214317) and next prime (1134110214329).
It is a cyclic number.
It is not a de Polignac number, because 1134110214323 - 214 = 1134110197939 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1134110214292 and 1134110214301.
It is not a weakly prime, because it can be changed into another prime (1134110214329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567055107161 + 567055107162.
It is an arithmetic number, because the mean of its divisors is an integer number (567055107162).
Almost surely, 21134110214323 is an apocalyptic number.
1134110214323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1134110214323 is an equidigital number, since it uses as much as digits as its factorization.
1134110214323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 1134110214323 its reverse (3234120114311), we get a palindrome (4368230328634).
The spelling of 1134110214323 in words is "one trillion, one hundred thirty-four billion, one hundred ten million, two hundred fourteen thousand, three hundred twenty-three".
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