11341103 has 2 divisors, whose sum is σ = 11341104. Its totient is φ = 11341102.

The previous prime is 11341097. The next prime is 11341171. The reversal of 11341103 is 30114311.

It is a weak prime.

It is an emirp because it is prime and its reverse (30114311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11341103 - 2⁴ = 11341087 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11341403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5670551 + 5670552.

It is an arithmetic number, because the mean of its divisors is an integer number (5670552).

Almost surely, 2^11341103 is an apocalyptic number.

11341103 is a deficient number, since it is larger than the sum of its proper divisors (1).

11341103 is an equidigital number, since it uses as much as digits as its factorization.

11341103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 11341103 is about 3367.6554158643. The cubic root of 11341103 is about 224.6734555305.

Adding to 11341103 its reverse (30114311), we get a palindrome (41455414).

The spelling of 11341103 in words is "eleven million, three hundred forty-one thousand, one hundred three".