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1134113131 is a prime number
BaseRepresentation
bin100001110011001…
…0011000101101011
32221001000220202001
41003212103011223
54310313110011
6304311551431
740050542164
oct10346230553
92831026661
101134113131
115321a4a88
1227798b577
13150c65b78
14aa89c76b
15698737c1
hex4399316b

1134113131 has 2 divisors, whose sum is σ = 1134113132. Its totient is φ = 1134113130.

The previous prime is 1134113069. The next prime is 1134113137. The reversal of 1134113131 is 1313114311.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1134113131 is a prime.

It is a super-2 number, since 2×11341131312 = 2572425187813246322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1134113099 and 1134113108.

It is not a weakly prime, because it can be changed into another prime (1134113137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567056565 + 567056566.

It is an arithmetic number, because the mean of its divisors is an integer number (567056566).

Almost surely, 21134113131 is an apocalyptic number.

1134113131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1134113131 is an equidigital number, since it uses as much as digits as its factorization.

1134113131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 108, while the sum is 19.

The square root of 1134113131 is about 33676.5961908266. The cubic root of 1134113131 is about 1042.8426701233.

Adding to 1134113131 its reverse (1313114311), we get a palindrome (2447227442).

The spelling of 1134113131 in words is "one billion, one hundred thirty-four million, one hundred thirteen thousand, one hundred thirty-one".