Base | Representation |
---|---|
bin | 10101000111111110… |
… | …00001100001110010 |
3 | 1002021101100201021010 |
4 | 22203333001201302 |
5 | 141211313022010 |
6 | 5113212011350 |
7 | 551021055213 |
oct | 124377014162 |
9 | 32241321233 |
10 | 11341142130 |
11 | 489a862a3a |
12 | 2246160b56 |
13 | 10b97cbab6 |
14 | 79831340a |
15 | 4659c8620 |
hex | 2a3fc1872 |
11341142130 has 16 divisors (see below), whose sum is σ = 27218741184. Its totient is φ = 3024304560.
The previous prime is 11341142101. The next prime is 11341142173. The reversal of 11341142130 is 3124114311.
11341142130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 11341142097 and 11341142106.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 189019006 + ... + 189019065.
It is an arithmetic number, because the mean of its divisors is an integer number (1701171324).
Almost surely, 211341142130 is an apocalyptic number.
11341142130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11341142130 is an abundant number, since it is smaller than the sum of its proper divisors (15877599054).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11341142130 is a wasteful number, since it uses less digits than its factorization.
11341142130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 378038081.
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 11341142130 its reverse (3124114311), we get a palindrome (14465256441).
The spelling of 11341142130 in words is "eleven billion, three hundred forty-one million, one hundred forty-two thousand, one hundred thirty".
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