Base | Representation |
---|---|
bin | 10101000111111111… |
… | …10000001001111101 |
3 | 1002021101201102020201 |
4 | 22203333300021331 |
5 | 141211340124432 |
6 | 5113220043501 |
7 | 551022512062 |
oct | 124377601175 |
9 | 32241642221 |
10 | 11341333117 |
11 | 489a983484 |
12 | 2246233591 |
13 | 10b98679ca |
14 | 798362c69 |
15 | 465a14ee7 |
hex | 2a3ff027d |
11341333117 has 2 divisors, whose sum is σ = 11341333118. Its totient is φ = 11341333116.
The previous prime is 11341333109. The next prime is 11341333123. The reversal of 11341333117 is 71133314311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8213615641 + 3127717476 = 90629^2 + 55926^2 .
It is an emirp because it is prime and its reverse (71133314311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11341333117 - 23 = 11341333109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11341333517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5670666558 + 5670666559.
It is an arithmetic number, because the mean of its divisors is an integer number (5670666559).
Almost surely, 211341333117 is an apocalyptic number.
It is an amenable number.
11341333117 is a deficient number, since it is larger than the sum of its proper divisors (1).
11341333117 is an equidigital number, since it uses as much as digits as its factorization.
11341333117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2268, while the sum is 28.
Adding to 11341333117 its reverse (71133314311), we get a palindrome (82474647428).
The spelling of 11341333117 in words is "eleven billion, three hundred forty-one million, three hundred thirty-three thousand, one hundred seventeen".
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