11341400117 has 2 divisors, whose sum is σ = 11341400118. Its totient is φ = 11341400116.

The previous prime is 11341400053. The next prime is 11341400159. The reversal of 11341400117 is 71100414311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10834519921 + 506880196 = 104089^2 + 22514^2 .

It is a cyclic number.

It is not a de Polignac number, because 11341400117 - 2⁶ = 11341400053 is a prime.

It is a super-2 number, since 2×11341400117² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11341400092 and 11341400101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11341400167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5670700058 + 5670700059.

It is an arithmetic number, because the mean of its divisors is an integer number (5670700059).

Almost surely, 2^11341400117 is an apocalyptic number.

It is an amenable number.

11341400117 is a deficient number, since it is larger than the sum of its proper divisors (1).

11341400117 is an equidigital number, since it uses as much as digits as its factorization.

11341400117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 336, while the sum is 23.

Adding to 11341400117 its reverse (71100414311), we get a palindrome (82441814428).

The spelling of 11341400117 in words is "eleven billion, three hundred forty-one million, four hundred thousand, one hundred seventeen".