113414011121 has 2 divisors, whose sum is σ = 113414011122. Its totient is φ = 113414011120.

The previous prime is 113414011111. The next prime is 113414011153. The reversal of 113414011121 is 121110414311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 112235050225 + 1178960896 = 335015^2 + 34336^2 .

It is an emirp because it is prime and its reverse (121110414311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113414011121 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113414011093 and 113414011102.

It is not a weakly prime, because it can be changed into another prime (113414011111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56707005560 + 56707005561.

It is an arithmetic number, because the mean of its divisors is an integer number (56707005561).

Almost surely, 2^113414011121 is an apocalyptic number.

It is an amenable number.

113414011121 is a deficient number, since it is larger than the sum of its proper divisors (1).

113414011121 is an equidigital number, since it uses as much as digits as its factorization.

113414011121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 20.

Adding to 113414011121 its reverse (121110414311), we get a palindrome (234524425432).

The spelling of 113414011121 in words is "one hundred thirteen billion, four hundred fourteen million, eleven thousand, one hundred twenty-one".