113414013142133 has 4 divisors (see below), whose sum is σ = 123724377973248. Its totient is φ = 103103648311020.

The previous prime is 113414013142121. The next prime is 113414013142181. The reversal of 113414013142133 is 331241310414311.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113414013142133 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 113414013142133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113414013112133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5155182415541 + ... + 5155182415562.

It is an arithmetic number, because the mean of its divisors is an integer number (30931094493312).

Almost surely, 2^{113414013142133} is an apocalyptic number.

It is an amenable number.

113414013142133 is a deficient number, since it is larger than the sum of its proper divisors (10310364831115).

113414013142133 is a wasteful number, since it uses less digits than its factorization.

113414013142133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10310364831114.

The product of its (nonzero) digits is 10368, while the sum is 32.

Adding to 113414013142133 its reverse (331241310414311), we get a palindrome (444655323556444).

The spelling of 113414013142133 in words is "one hundred thirteen trillion, four hundred fourteen billion, thirteen million, one hundred forty-two thousand, one hundred thirty-three".