Base | Representation |
---|---|
bin | 11001110010011001001001… |
… | …000001000001001101111111 |
3 | 112212120021200211011001022221 |
4 | 121302121021001001031333 |
5 | 104331134120121001304 |
6 | 1041113422132550211 |
7 | 32613620622006145 |
oct | 3162311101011577 |
9 | 485507624131287 |
10 | 113414131422079 |
11 | 3315673253a894 |
12 | 10878503182367 |
13 | 4b38ba30443b7 |
14 | 20013b7b23595 |
15 | d1a266293054 |
hex | 67264904137f |
113414131422079 has 2 divisors, whose sum is σ = 113414131422080. Its totient is φ = 113414131422078.
The previous prime is 113414131422041. The next prime is 113414131422133. The reversal of 113414131422079 is 970224131414311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113414131422079 - 229 = 113413594551167 is a prime.
It is a super-3 number, since 3×1134141314220793 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113414131422679) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56707065711039 + 56707065711040.
It is an arithmetic number, because the mean of its divisors is an integer number (56707065711040).
Almost surely, 2113414131422079 is an apocalyptic number.
113414131422079 is a deficient number, since it is larger than the sum of its proper divisors (1).
113414131422079 is an equidigital number, since it uses as much as digits as its factorization.
113414131422079 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 145152, while the sum is 43.
The spelling of 113414131422079 in words is "one hundred thirteen trillion, four hundred fourteen billion, one hundred thirty-one million, four hundred twenty-two thousand, seventy-nine".
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