Base | Representation |
---|---|
bin | 1010010100001010000011… |
… | …1101000101111011101011 |
3 | 1111011020011122101110112121 |
4 | 2211002200331011323223 |
5 | 2441304203442443313 |
6 | 40042101303052111 |
7 | 2250250545441253 |
oct | 245024075057353 |
9 | 44136148343477 |
10 | 11341414031083 |
11 | 3682959606784 |
12 | 1332060741037 |
13 | 64364c2572a6 |
14 | 2b2cda9aa963 |
15 | 14a039a6728d |
hex | a50a0f45eeb |
11341414031083 has 2 divisors, whose sum is σ = 11341414031084. Its totient is φ = 11341414031082.
The previous prime is 11341414031039. The next prime is 11341414031113. The reversal of 11341414031083 is 38013041414311.
11341414031083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11341414031083 is a prime.
It is not a weakly prime, because it can be changed into another prime (11341414331083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5670707015541 + 5670707015542.
It is an arithmetic number, because the mean of its divisors is an integer number (5670707015542).
Almost surely, 211341414031083 is an apocalyptic number.
11341414031083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11341414031083 is an equidigital number, since it uses as much as digits as its factorization.
11341414031083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 34.
Adding to 11341414031083 its reverse (38013041414311), we get a palindrome (49354455445394).
The spelling of 11341414031083 in words is "eleven trillion, three hundred forty-one billion, four hundred fourteen million, thirty-one thousand, eighty-three".
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