Base | Representation |
---|---|
bin | 10000100000010000001… |
… | …100100111110001011101 |
3 | 11000102102101100110220011 |
4 | 100200100030213301131 |
5 | 122040211114011422 |
6 | 2225003530523221 |
7 | 144640060242664 |
oct | 20402014476135 |
9 | 4012371313804 |
10 | 1134143110237 |
11 | 3a7a95245075 |
12 | 16397a296511 |
13 | 82c4561a997 |
14 | 3cc6dc79ddb |
15 | 1e77d1bd077 |
hex | 10810327c5d |
1134143110237 has 2 divisors, whose sum is σ = 1134143110238. Its totient is φ = 1134143110236.
The previous prime is 1134143110187. The next prime is 1134143110271. The reversal of 1134143110237 is 7320113414311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1134127022116 + 16088121 = 1064954^2 + 4011^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1134143110237 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1134143110199 and 1134143110208.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1134143110637) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567071555118 + 567071555119.
It is an arithmetic number, because the mean of its divisors is an integer number (567071555119).
Almost surely, 21134143110237 is an apocalyptic number.
It is an amenable number.
1134143110237 is a deficient number, since it is larger than the sum of its proper divisors (1).
1134143110237 is an equidigital number, since it uses as much as digits as its factorization.
1134143110237 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 31.
Adding to 1134143110237 its reverse (7320113414311), we get a palindrome (8454256524548).
The spelling of 1134143110237 in words is "one trillion, one hundred thirty-four billion, one hundred forty-three million, one hundred ten thousand, two hundred thirty-seven".
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