Search a number
-
+
1134143110237 is a prime number
BaseRepresentation
bin10000100000010000001…
…100100111110001011101
311000102102101100110220011
4100200100030213301131
5122040211114011422
62225003530523221
7144640060242664
oct20402014476135
94012371313804
101134143110237
113a7a95245075
1216397a296511
1382c4561a997
143cc6dc79ddb
151e77d1bd077
hex10810327c5d

1134143110237 has 2 divisors, whose sum is σ = 1134143110238. Its totient is φ = 1134143110236.

The previous prime is 1134143110187. The next prime is 1134143110271. The reversal of 1134143110237 is 7320113414311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1134127022116 + 16088121 = 1064954^2 + 4011^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1134143110237 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1134143110199 and 1134143110208.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1134143110637) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567071555118 + 567071555119.

It is an arithmetic number, because the mean of its divisors is an integer number (567071555119).

Almost surely, 21134143110237 is an apocalyptic number.

It is an amenable number.

1134143110237 is a deficient number, since it is larger than the sum of its proper divisors (1).

1134143110237 is an equidigital number, since it uses as much as digits as its factorization.

1134143110237 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 31.

Adding to 1134143110237 its reverse (7320113414311), we get a palindrome (8454256524548).

The spelling of 1134143110237 in words is "one trillion, one hundred thirty-four billion, one hundred forty-three million, one hundred ten thousand, two hundred thirty-seven".