Base | Representation |
---|---|
bin | 1010010100001010001010… |
… | …0100110000000001110111 |
3 | 1111011020020112112000020122 |
4 | 2211002202210300001313 |
5 | 2441304232422014333 |
6 | 40042104113322155 |
7 | 2250251325424505 |
oct | 245024244600167 |
9 | 44136215460218 |
10 | 11341441204343 |
11 | 3682972986418 |
12 | 133206986635b |
13 | 643654a7c743 |
14 | 2b2d00441675 |
15 | 14a03c133798 |
hex | a50a2930077 |
11341441204343 has 2 divisors, whose sum is σ = 11341441204344. Its totient is φ = 11341441204342.
The previous prime is 11341441204321. The next prime is 11341441204363. The reversal of 11341441204343 is 34340214414311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11341441204343 - 218 = 11341440942199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11341441204363) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5670720602171 + 5670720602172.
It is an arithmetic number, because the mean of its divisors is an integer number (5670720602172).
Almost surely, 211341441204343 is an apocalyptic number.
11341441204343 is a deficient number, since it is larger than the sum of its proper divisors (1).
11341441204343 is an equidigital number, since it uses as much as digits as its factorization.
11341441204343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 11341441204343 its reverse (34340214414311), we get a palindrome (45681655618654).
The spelling of 11341441204343 in words is "eleven trillion, three hundred forty-one billion, four hundred forty-one million, two hundred four thousand, three hundred forty-three".
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