Base | Representation |
---|---|
bin | 1010010100001011011000… |
… | …1011000000011010000111 |
3 | 1111011021002110012120002211 |
4 | 2211002312023000122013 |
5 | 2441310421110000012 |
6 | 40042200500444251 |
7 | 2250262430225446 |
oct | 245026613003207 |
9 | 44137073176084 |
10 | 11341770000007 |
11 | 3683021538477 |
12 | 133213b9a9687 |
13 | 6436a7c202a5 |
14 | 2b2d31d8cd5d |
15 | 14a05ae2e6a7 |
hex | a50b62c0687 |
11341770000007 has 2 divisors, whose sum is σ = 11341770000008. Its totient is φ = 11341770000006.
The previous prime is 11341769999999. The next prime is 11341770000061. The reversal of 11341770000007 is 70000007714311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11341770000007 - 23 = 11341769999999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11341770000707) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5670885000003 + 5670885000004.
It is an arithmetic number, because the mean of its divisors is an integer number (5670885000004).
Almost surely, 211341770000007 is an apocalyptic number.
11341770000007 is a deficient number, since it is larger than the sum of its proper divisors (1).
11341770000007 is an equidigital number, since it uses as much as digits as its factorization.
11341770000007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4116, while the sum is 31.
Adding to 11341770000007 its reverse (70000007714311), we get a palindrome (81341777714318).
The spelling of 11341770000007 in words is "eleven trillion, three hundred forty-one billion, seven hundred seventy million, seven", and thus it is an aban number.
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