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1134231341281 is a prime number
BaseRepresentation
bin10000100000010101011…
…101001100100011100001
311000102122112101002010121
4100200111131030203201
5122040401210410111
62225020402000241
7144642211220233
oct20402535144341
94012575332117
101134231341281
113a8030028395
121639a3946081
1382c5a9a06bc
143cc7b886253
151e785cea871
hex1081574c8e1

1134231341281 has 2 divisors, whose sum is σ = 1134231341282. Its totient is φ = 1134231341280.

The previous prime is 1134231341213. The next prime is 1134231341323. The reversal of 1134231341281 is 1821431324311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1051873820881 + 82357520400 = 1025609^2 + 286980^2 .

It is an emirp because it is prime and its reverse (1821431324311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1134231341281 - 225 = 1134197786849 is a prime.

It is a super-2 number, since 2×11342313412812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1134231345281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567115670640 + 567115670641.

It is an arithmetic number, because the mean of its divisors is an integer number (567115670641).

Almost surely, 21134231341281 is an apocalyptic number.

It is an amenable number.

1134231341281 is a deficient number, since it is larger than the sum of its proper divisors (1).

1134231341281 is an equidigital number, since it uses as much as digits as its factorization.

1134231341281 is an evil number, because the sum of its binary digits is even.

The product of its digits is 13824, while the sum is 34.

Adding to 1134231341281 its reverse (1821431324311), we get a palindrome (2955662665592).

The spelling of 1134231341281 in words is "one trillion, one hundred thirty-four billion, two hundred thirty-one million, three hundred forty-one thousand, two hundred eighty-one".