Base | Representation |
---|---|
bin | 10101001000001100… |
… | …01100110000101011 |
3 | 1002021111220021112102 |
4 | 22210012030300223 |
5 | 141212303220042 |
6 | 5113320204015 |
7 | 551043051221 |
oct | 124406146053 |
9 | 32244807472 |
10 | 11343023147 |
11 | 48a09281a5 |
12 | 224690960b |
13 | 10ba00a021 |
14 | 798682b11 |
15 | 465c4ab32 |
hex | 2a418cc2b |
11343023147 has 2 divisors, whose sum is σ = 11343023148. Its totient is φ = 11343023146.
The previous prime is 11343023129. The next prime is 11343023149. The reversal of 11343023147 is 74132034311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11343023147 - 220 = 11341974571 is a prime.
It is a super-2 number, since 2×113430231472 (a number of 21 digits) contains 22 as substring.
Together with 11343023149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (11343023149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5671511573 + 5671511574.
It is an arithmetic number, because the mean of its divisors is an integer number (5671511574).
Almost surely, 211343023147 is an apocalyptic number.
11343023147 is a deficient number, since it is larger than the sum of its proper divisors (1).
11343023147 is an equidigital number, since it uses as much as digits as its factorization.
11343023147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 29.
Adding to 11343023147 its reverse (74132034311), we get a palindrome (85475057458).
The spelling of 11343023147 in words is "eleven billion, three hundred forty-three million, twenty-three thousand, one hundred forty-seven".
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