Base | Representation |
---|---|
bin | 11001110010101000111100… |
… | …100110111111111000000011 |
3 | 112212121220111121102211020002 |
4 | 121302220330212333320003 |
5 | 104331423344401042202 |
6 | 1041125310203510215 |
7 | 32615061323161256 |
oct | 3162507446777003 |
9 | 485556447384202 |
10 | 113431103143427 |
11 | 33162951644283 |
12 | 1087b85ab2836b |
13 | 4b3a679216174 |
14 | 2002147b6109d |
15 | d1a90b231302 |
hex | 672a3c9bfe03 |
113431103143427 has 2 divisors, whose sum is σ = 113431103143428. Its totient is φ = 113431103143426.
The previous prime is 113431103143403. The next prime is 113431103143487. The reversal of 113431103143427 is 724341301134311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113431103143427 - 222 = 113431098949123 is a prime.
It is not a weakly prime, because it can be changed into another prime (113431103143487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56715551571713 + 56715551571714.
It is an arithmetic number, because the mean of its divisors is an integer number (56715551571714).
Almost surely, 2113431103143427 is an apocalyptic number.
113431103143427 is a deficient number, since it is larger than the sum of its proper divisors (1).
113431103143427 is an equidigital number, since it uses as much as digits as its factorization.
113431103143427 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72576, while the sum is 38.
Adding to 113431103143427 its reverse (724341301134311), we get a palindrome (837772404277738).
The spelling of 113431103143427 in words is "one hundred thirteen trillion, four hundred thirty-one billion, one hundred three million, one hundred forty-three thousand, four hundred twenty-seven".
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