11343130320037 has 2 divisors, whose sum is σ = 11343130320038. Its totient is φ = 11343130320036.

The previous prime is 11343130319971. The next prime is 11343130320061. The reversal of 11343130320037 is 73002303134311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9879492503556 + 1463637816481 = 3143166^2 + 1209809^2 .

It is an emirp because it is prime and its reverse (73002303134311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11343130320037 - 2⁷ = 11343130319909 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11343130319990 and 11343130320008.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11343130320437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5671565160018 + 5671565160019.

It is an arithmetic number, because the mean of its divisors is an integer number (5671565160019).

Almost surely, 2^{11343130320037} is an apocalyptic number.

It is an amenable number.

11343130320037 is a deficient number, since it is larger than the sum of its proper divisors (1).

11343130320037 is an equidigital number, since it uses as much as digits as its factorization.

11343130320037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13608, while the sum is 31.

Adding to 11343130320037 its reverse (73002303134311), we get a palindrome (84345433454348).

The spelling of 11343130320037 in words is "eleven trillion, three hundred forty-three billion, one hundred thirty million, three hundred twenty thousand, thirty-seven".