Base | Representation |
---|---|
bin | 10000100000011010011… |
… | …001000000101111101001 |
3 | 11000102212022011012110121 |
4 | 100200122121000233221 |
5 | 122041033404133114 |
6 | 2225032520243241 |
7 | 144644235011035 |
oct | 20403231005751 |
9 | 4012768135417 |
10 | 1134314130409 |
11 | 3a8072834059 |
12 | 163a07610521 |
13 | 82c71b99455 |
14 | 3cc888771c5 |
15 | 1e78d200a24 |
hex | 1081a640be9 |
1134314130409 has 2 divisors, whose sum is σ = 1134314130410. Its totient is φ = 1134314130408.
The previous prime is 1134314130361. The next prime is 1134314130449. The reversal of 1134314130409 is 9040314134311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 905595850384 + 228718280025 = 951628^2 + 478245^2 .
It is a cyclic number.
It is not a de Polignac number, because 1134314130409 - 211 = 1134314128361 is a prime.
It is not a weakly prime, because it can be changed into another prime (1134314130449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567157065204 + 567157065205.
It is an arithmetic number, because the mean of its divisors is an integer number (567157065205).
Almost surely, 21134314130409 is an apocalyptic number.
It is an amenable number.
1134314130409 is a deficient number, since it is larger than the sum of its proper divisors (1).
1134314130409 is an equidigital number, since it uses as much as digits as its factorization.
1134314130409 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 34.
The spelling of 1134314130409 in words is "one trillion, one hundred thirty-four billion, three hundred fourteen million, one hundred thirty thousand, four hundred nine".
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