Base | Representation |
---|---|
bin | 1010010100010000011111… |
… | …1101010100100010110111 |
3 | 1111011101122002010201001111 |
4 | 2211010013331110202313 |
5 | 2441321223342103213 |
6 | 40042544554335451 |
7 | 2250341431243003 |
oct | 245040775244267 |
9 | 44141562121044 |
10 | 11343142144183 |
11 | 3683666030723 |
12 | 133246342a587 |
13 | 643866297a15 |
14 | 2b30222cd703 |
15 | 14a0db620a3d |
hex | a5107f548b7 |
11343142144183 has 2 divisors, whose sum is σ = 11343142144184. Its totient is φ = 11343142144182.
The previous prime is 11343142144043. The next prime is 11343142144241. The reversal of 11343142144183 is 38144124134311.
11343142144183 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11343142144183 - 213 = 11343142135991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11343142144483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5671571072091 + 5671571072092.
It is an arithmetic number, because the mean of its divisors is an integer number (5671571072092).
Almost surely, 211343142144183 is an apocalyptic number.
11343142144183 is a deficient number, since it is larger than the sum of its proper divisors (1).
11343142144183 is an equidigital number, since it uses as much as digits as its factorization.
11343142144183 is an evil number, because the sum of its binary digits is even.
The product of its digits is 110592, while the sum is 40.
Adding to 11343142144183 its reverse (38144124134311), we get a palindrome (49487266278494).
The spelling of 11343142144183 in words is "eleven trillion, three hundred forty-three billion, one hundred forty-two million, one hundred forty-four thousand, one hundred eighty-three".
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