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11343210125251 is a prime number
BaseRepresentation
bin1010010100010000110000…
…0000101001011111000011
31111011101210211001111112211
42211010030000221133003
52441321343243002001
640042555423402551
72250343215130354
oct245041400513703
944141724044484
1011343210125251
1136836a0442924
121332482153457
136438773aa5c4
142b302b347d2b
1514a0e259d351
hexa510c0297c3

11343210125251 has 2 divisors, whose sum is σ = 11343210125252. Its totient is φ = 11343210125250.

The previous prime is 11343210125227. The next prime is 11343210125311. The reversal of 11343210125251 is 15252101234311.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11343210125251 is a prime.

It is not a weakly prime, because it can be changed into another prime (11343240125251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5671605062625 + 5671605062626.

It is an arithmetic number, because the mean of its divisors is an integer number (5671605062626).

Almost surely, 211343210125251 is an apocalyptic number.

11343210125251 is a deficient number, since it is larger than the sum of its proper divisors (1).

11343210125251 is an equidigital number, since it uses as much as digits as its factorization.

11343210125251 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7200, while the sum is 31.

Adding to 11343210125251 its reverse (15252101234311), we get a palindrome (26595311359562).

The spelling of 11343210125251 in words is "eleven trillion, three hundred forty-three billion, two hundred ten million, one hundred twenty-five thousand, two hundred fifty-one".