Base | Representation |
---|---|
bin | 1010010100010000110000… |
… | …0000101001011110101011 |
3 | 1111011101210211001111111221 |
4 | 2211010030000221132223 |
5 | 2441321343243001402 |
6 | 40042555423402511 |
7 | 2250343215130321 |
oct | 245041400513653 |
9 | 44141724044457 |
10 | 11343210125227 |
11 | 36836a0442902 |
12 | 1332482153437 |
13 | 6438773aa5a6 |
14 | 2b302b347d11 |
15 | 14a0e259d337 |
hex | a510c0297ab |
11343210125227 has 2 divisors, whose sum is σ = 11343210125228. Its totient is φ = 11343210125226.
The previous prime is 11343210125171. The next prime is 11343210125251. The reversal of 11343210125227 is 72252101234311.
It is a strong prime.
It is an emirp because it is prime and its reverse (72252101234311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11343210125227 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11343210125192 and 11343210125201.
It is not a weakly prime, because it can be changed into another prime (11343810125227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5671605062613 + 5671605062614.
It is an arithmetic number, because the mean of its divisors is an integer number (5671605062614).
Almost surely, 211343210125227 is an apocalyptic number.
11343210125227 is a deficient number, since it is larger than the sum of its proper divisors (1).
11343210125227 is an equidigital number, since it uses as much as digits as its factorization.
11343210125227 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 34.
Adding to 11343210125227 its reverse (72252101234311), we get a palindrome (83595311359538).
The spelling of 11343210125227 in words is "eleven trillion, three hundred forty-three billion, two hundred ten million, one hundred twenty-five thousand, two hundred twenty-seven".
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