Base | Representation |
---|---|
bin | 1101100001011… |
… | …01101000011001 |
3 | 21220102222222102 |
4 | 12300231220121 |
5 | 213014324423 |
6 | 15131133145 |
7 | 2545110533 |
oct | 660555031 |
9 | 256388872 |
10 | 113433113 |
11 | 59036a82 |
12 | 31ba41b5 |
13 | 1a667bb1 |
14 | 110ca853 |
15 | 9e59c28 |
hex | 6c2da19 |
113433113 has 2 divisors, whose sum is σ = 113433114. Its totient is φ = 113433112.
The previous prime is 113433109. The next prime is 113433119. The reversal of 113433113 is 311334311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 98168464 + 15264649 = 9908^2 + 3907^2 .
It is a cyclic number.
It is not a de Polignac number, because 113433113 - 22 = 113433109 is a prime.
It is a super-2 number, since 2×1134331132 = 25734142249741538, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (113433119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56716556 + 56716557.
It is an arithmetic number, because the mean of its divisors is an integer number (56716557).
Almost surely, 2113433113 is an apocalyptic number.
It is an amenable number.
113433113 is a deficient number, since it is larger than the sum of its proper divisors (1).
113433113 is an equidigital number, since it uses as much as digits as its factorization.
113433113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 324, while the sum is 20.
The square root of 113433113 is about 10650.4982512557. The cubic root of 113433113 is about 484.0757016235.
Adding to 113433113 its reverse (311334311), we get a palindrome (424767424).
The spelling of 113433113 in words is "one hundred thirteen million, four hundred thirty-three thousand, one hundred thirteen".
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