113433119 has 2 divisors, whose sum is σ = 113433120. Its totient is φ = 113433118.

The previous prime is 113433113. The next prime is 113433121. The reversal of 113433119 is 911334311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113433119 is a prime.

It is a super-2 number, since 2×113433119² = 25734144972136322, which contains 22 as substring.

Together with 113433121, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113433113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56716559 + 56716560.

It is an arithmetic number, because the mean of its divisors is an integer number (56716560).

Almost surely, 2^113433119 is an apocalyptic number.

113433119 is a deficient number, since it is larger than the sum of its proper divisors (1).

113433119 is an equidigital number, since it uses as much as digits as its factorization.

113433119 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 972, while the sum is 26.

The square root of 113433119 is about 10650.4985329326. The cubic root of 113433119 is about 484.0757101585.

The spelling of 113433119 in words is "one hundred thirteen million, four hundred thirty-three thousand, one hundred nineteen".