Base | Representation |
---|---|
bin | 110100110100100100… |
… | …1000001101000001100 |
3 | 101211210100102201020101 |
4 | 1221221021001220030 |
5 | 3324302334421330 |
6 | 124035505300444 |
7 | 11123656432255 |
oct | 1515111015014 |
9 | 354710381211 |
10 | 113433123340 |
11 | 4411a04a529 |
12 | 19b98634724 |
13 | a90984c534 |
14 | 56c1133b2c |
15 | 2e3d6e44ca |
hex | 1a69241a0c |
113433123340 has 12 divisors (see below), whose sum is σ = 238209559056. Its totient is φ = 45373249328.
The previous prime is 113433123337. The next prime is 113433123361. The reversal of 113433123340 is 43321334311.
It is a junction number, because it is equal to n+sod(n) for n = 113433123299 and 113433123308.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2835828064 + ... + 2835828103.
It is an arithmetic number, because the mean of its divisors is an integer number (19850796588).
Almost surely, 2113433123340 is an apocalyptic number.
113433123340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113433123340 is an abundant number, since it is smaller than the sum of its proper divisors (124776435716).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113433123340 is a wasteful number, since it uses less digits than its factorization.
113433123340 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5671656176 (or 5671656174 counting only the distinct ones).
The product of its (nonzero) digits is 7776, while the sum is 28.
Adding to 113433123340 its reverse (43321334311), we get a palindrome (156754457651).
The spelling of 113433123340 in words is "one hundred thirteen billion, four hundred thirty-three million, one hundred twenty-three thousand, three hundred forty".
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