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11343323223124 = 222835830805781
BaseRepresentation
bin1010010100010001001011…
…0000000101010001010100
31111011102002200212110122221
42211010102300011101110
52441322111221114444
640043014543432124
72250346060343644
oct245042260052124
944142080773587
1011343323223124
11368374926aa42
1213324b3bb5644
13643894958a19
142b303c388524
1514a0ec48da84
hexa5112c05454

11343323223124 has 6 divisors (see below), whose sum is σ = 19850815640474. Its totient is φ = 5671661611560.

The previous prime is 11343323223107. The next prime is 11343323223137. The reversal of 11343323223124 is 42132232334311.

It can be written as a sum of positive squares in only one way, i.e., 9801082126224 + 1542241096900 = 3130668^2 + 1241870^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 11343323223124.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1417915402887 + ... + 1417915402894.

Almost surely, 211343323223124 is an apocalyptic number.

It is an amenable number.

11343323223124 is a deficient number, since it is larger than the sum of its proper divisors (8507492417350).

11343323223124 is a wasteful number, since it uses less digits than its factorization.

11343323223124 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2835830805785 (or 2835830805783 counting only the distinct ones).

The product of its digits is 62208, while the sum is 34.

Adding to 11343323223124 its reverse (42132232334311), we get a palindrome (53475555557435).

The spelling of 11343323223124 in words is "eleven trillion, three hundred forty-three billion, three hundred twenty-three million, two hundred twenty-three thousand, one hundred twenty-four".

Divisors: 1 2 4 2835830805781 5671661611562 11343323223124