Base | Representation |
---|---|
bin | 11001110010101011000001… |
… | …000011011110110010111111 |
3 | 112212122010020110122010101211 |
4 | 121302223001003132302333 |
5 | 104331442422222440443 |
6 | 1041130314502145251 |
7 | 32615200354314046 |
oct | 3162530103366277 |
9 | 485563213563354 |
10 | 113433325202623 |
11 | 33163891970238 |
12 | 1088017b122227 |
13 | 4b3a94169c2aa |
14 | 20022b8d0155d |
15 | d1a9db35919d |
hex | 672ac10decbf |
113433325202623 has 2 divisors, whose sum is σ = 113433325202624. Its totient is φ = 113433325202622.
The previous prime is 113433325202611. The next prime is 113433325202647. The reversal of 113433325202623 is 326202523334311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113433325202623 - 229 = 113432788331711 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113433325202663) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56716662601311 + 56716662601312.
It is an arithmetic number, because the mean of its divisors is an integer number (56716662601312).
Almost surely, 2113433325202623 is an apocalyptic number.
113433325202623 is a deficient number, since it is larger than the sum of its proper divisors (1).
113433325202623 is an equidigital number, since it uses as much as digits as its factorization.
113433325202623 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 466560, while the sum is 40.
Adding to 113433325202623 its reverse (326202523334311), we get a palindrome (439635848536934).
The spelling of 113433325202623 in words is "one hundred thirteen trillion, four hundred thirty-three billion, three hundred twenty-five million, two hundred two thousand, six hundred twenty-three".
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