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113433432001 is a prime number
BaseRepresentation
bin110100110100100101…
…0001100111111000001
3101211210101000101122021
41221221022030333001
53324302424311001
6124035520041441
711123662156201
oct1515112147701
9354711011567
10113433432001
114411a24041a
1219b98763281
13a909929b86
1456c11b4401
152e3d755ba1
hex1a6928cfc1

113433432001 has 2 divisors, whose sum is σ = 113433432002. Its totient is φ = 113433432000.

The previous prime is 113433431971. The next prime is 113433432011. The reversal of 113433432001 is 100234334311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 80236227600 + 33197204401 = 283260^2 + 182201^2 .

It is an emirp because it is prime and its reverse (100234334311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113433432001 - 219 = 113432907713 is a prime.

It is not a weakly prime, because it can be changed into another prime (113433432011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56716716000 + 56716716001.

It is an arithmetic number, because the mean of its divisors is an integer number (56716716001).

Almost surely, 2113433432001 is an apocalyptic number.

It is an amenable number.

113433432001 is a deficient number, since it is larger than the sum of its proper divisors (1).

113433432001 is an equidigital number, since it uses as much as digits as its factorization.

113433432001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 113433432001 its reverse (100234334311), we get a palindrome (213667766312).

The spelling of 113433432001 in words is "one hundred thirteen billion, four hundred thirty-three million, four hundred thirty-two thousand, one".