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1134335544401 is a prime number
BaseRepresentation
bin10000100000011011101…
…010101100110001010001
311000102220210110010221102
4100200123222230301101
5122041104344410101
62225035003234145
7144644615016353
oct20403352546121
94012823403842
101134335544401
113a808392a774
12163a12818955
1382c76456357
143cc8b64d0d3
151e79003086b
hex1081baacc51

1134335544401 has 2 divisors, whose sum is σ = 1134335544402. Its totient is φ = 1134335544400.

The previous prime is 1134335544379. The next prime is 1134335544427. The reversal of 1134335544401 is 1044455334311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 611062707025 + 523272837376 = 781705^2 + 723376^2 .

It is an emirp because it is prime and its reverse (1044455334311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1134335544401 - 210 = 1134335543377 is a prime.

It is not a weakly prime, because it can be changed into another prime (1134335544701) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567167772200 + 567167772201.

It is an arithmetic number, because the mean of its divisors is an integer number (567167772201).

Almost surely, 21134335544401 is an apocalyptic number.

It is an amenable number.

1134335544401 is a deficient number, since it is larger than the sum of its proper divisors (1).

1134335544401 is an equidigital number, since it uses as much as digits as its factorization.

1134335544401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 172800, while the sum is 38.

The spelling of 1134335544401 in words is "one trillion, one hundred thirty-four billion, three hundred thirty-five million, five hundred forty-four thousand, four hundred one".